5-(n-7)=4(n+2)

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Solution for 5-(n-7)=4(n+2) equation: 



5-(n-7)=4(n+2)

We move all terms to the left:

5-(n-7)-(4(n+2))=0

We get rid of parentheses

-n-(4(n+2))+7+5=0



We calculate terms in parentheses: -(4(n+2)), so:

4(n+2)

We multiply parentheses

4n+8

Back to the equation:

-(4n+8)



We add all the numbers together, and all the variables

-1n-(4n+8)+12=0

We get rid of parentheses

-1n-4n-8+12=0

We add all the numbers together, and all the variables

-5n+4=0

We move all terms containing n to the left, all other terms to the right

-5n=-4

n=-4/-5

n=4/5

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