5-(r+3)=1+2(r-3)

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Solution for 5-(r+3)=1+2(r-3) equation: 



5-(r+3)=1+2(r-3)

We move all terms to the left:

5-(r+3)-(1+2(r-3))=0

We get rid of parentheses

-r-(1+2(r-3))-3+5=0



We calculate terms in parentheses: -(1+2(r-3)), so:

1+2(r-3)

determiningTheFunctionDomain
2(r-3)+1

We multiply parentheses

2r-6+1

We add all the numbers together, and all the variables

2r-5

Back to the equation:

-(2r-5)



We add all the numbers together, and all the variables

-1r-(2r-5)+2=0

We get rid of parentheses

-1r-2r+5+2=0

We add all the numbers together, and all the variables

-3r+7=0

We move all terms containing r to the left, all other terms to the right

-3r=-7

r=-7/-3

r=2+1/3

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