5-(t+2)=-1+2(t-3)

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Solution for 5-(t+2)=-1+2(t-3) equation: 



5-(t+2)=-1+2(t-3)

We move all terms to the left:

5-(t+2)-(-1+2(t-3))=0

We get rid of parentheses

-t-(-1+2(t-3))-2+5=0



We calculate terms in parentheses: -(-1+2(t-3)), so:

-1+2(t-3)

determiningTheFunctionDomain
2(t-3)-1

We multiply parentheses

2t-6-1

We add all the numbers together, and all the variables

2t-7

Back to the equation:

-(2t-7)



We add all the numbers together, and all the variables

-1t-(2t-7)+3=0

We get rid of parentheses

-1t-2t+7+3=0

We add all the numbers together, and all the variables

-3t+10=0

We move all terms containing t to the left, all other terms to the right

-3t=-10

t=-10/-3

t=3+1/3

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