5-(t+3)=2(t-1)+13

Solution for 5-(t+3)=2(t-1)+13 equation:

5-(t+3)=2(t-1)+13

We move all terms to the left:

5-(t+3)-(2(t-1)+13)=0

We get rid of parentheses

-t-(2(t-1)+13)-3+5=0


We calculate terms in parentheses: -(2(t-1)+13), so:

2(t-1)+13

We multiply parentheses

2t-2+13

We add all the numbers together, and all the variables

2t+11

Back to the equation:

-(2t+11)


We add all the numbers together, and all the variables

-1t-(2t+11)+2=0

We get rid of parentheses

-1t-2t-11+2=0

We add all the numbers together, and all the variables

-3t-9=0

We move all terms containing t to the left, all other terms to the right

-3t=9

t=9/-3

t=-3