5-(x-2)=2(x+3)+7

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Solution for 5-(x-2)=2(x+3)+7 equation: 



5-(x-2)=2(x+3)+7

We move all terms to the left:

5-(x-2)-(2(x+3)+7)=0

We get rid of parentheses

-x-(2(x+3)+7)+2+5=0



We calculate terms in parentheses: -(2(x+3)+7), so:

2(x+3)+7

We multiply parentheses

2x+6+7

We add all the numbers together, and all the variables

2x+13

Back to the equation:

-(2x+13)



We add all the numbers together, and all the variables

-1x-(2x+13)+7=0

We get rid of parentheses

-1x-2x-13+7=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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