5-(x-3)-6=10-(x+2)

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Solution for 5-(x-3)-6=10-(x+2) equation: 



5-(x-3)-6=10-(x+2)

We move all terms to the left:

5-(x-3)-6-(10-(x+2))=0

We add all the numbers together, and all the variables

-(x-3)-(10-(x+2))-1=0

We get rid of parentheses

-x-(10-(x+2))+3-1=0



We calculate terms in parentheses: -(10-(x+2)), so:

10-(x+2)

determiningTheFunctionDomain
-(x+2)+10

We get rid of parentheses

-x-2+10

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

-1x-(-1x+8)+2=0

We get rid of parentheses

-1x+1x-8+2=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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