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5-(x-3)=4x(3x-8)
We move all terms to the left:
5-(x-3)-(4x(3x-8))=0
We get rid of parentheses
-x-(4x(3x-8))+3+5=0
We calculate terms in parentheses: -(4x(3x-8)), so:We add all the numbers together, and all the variables
4x(3x-8)
We multiply parentheses
12x^2-32x
Back to the equation:
-(12x^2-32x)
-1x-(12x^2-32x)+8=0
We get rid of parentheses
-12x^2-1x+32x+8=0
We add all the numbers together, and all the variables
-12x^2+31x+8=0
a = -12; b = 31; c = +8;
Δ = b2-4ac
Δ = 312-4·(-12)·8
Δ = 1345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{1345}}{2*-12}=\frac{-31-\sqrt{1345}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{1345}}{2*-12}=\frac{-31+\sqrt{1345}}{-24} $
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