5-(x-4)=7(x+3)

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Solution for 5-(x-4)=7(x+3) equation: 



5-(x-4)=7(x+3)

We move all terms to the left:

5-(x-4)-(7(x+3))=0

We get rid of parentheses

-x-(7(x+3))+4+5=0



We calculate terms in parentheses: -(7(x+3)), so:

7(x+3)

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We add all the numbers together, and all the variables

-1x-(7x+21)+9=0

We get rid of parentheses

-1x-7x-21+9=0

We add all the numbers together, and all the variables

-8x-12=0

We move all terms containing x to the left, all other terms to the right

-8x=12

x=12/-8

x=-1+1/2

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