5-(x/)3=(x/2)+6

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Solution for 5-(x/)3=(x/2)+6 equation:



5-(x/)3=(x/2)+6
We move all terms to the left:
5-(x/)3-((x/2)+6)=0
We add all the numbers together, and all the variables
-(+x/)3-((+x/2)+6)+5=0
We multiply parentheses
-3x-((+x/2)+6)+5=0
We multiply all the terms by the denominator
-3x*2)+6)-((+x+5*2)+6)=0
We add all the numbers together, and all the variables
-3x*2)+6)-((x+10)+6)=0
We add all the numbers together, and all the variables
-3x*2)+6)-((x=0
Wy multiply elements
-6x^2=0
a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$

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