5-(y-4)=7(2y+1)

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Solution for 5-(y-4)=7(2y+1) equation:



5-(y-4)=7(2y+1)
We move all terms to the left:
5-(y-4)-(7(2y+1))=0
We get rid of parentheses
-y-(7(2y+1))+4+5=0
We calculate terms in parentheses: -(7(2y+1)), so:
7(2y+1)
We multiply parentheses
14y+7
Back to the equation:
-(14y+7)
We add all the numbers together, and all the variables
-1y-(14y+7)+9=0
We get rid of parentheses
-1y-14y-7+9=0
We add all the numbers together, and all the variables
-15y+2=0
We move all terms containing y to the left, all other terms to the right
-15y=-2
y=-2/-15
y=2/15

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