5-(y-4)=7(2y+1)

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Solution for 5-(y-4)=7(2y+1) equation: 



5-(y-4)=7(2y+1)

We move all terms to the left:

5-(y-4)-(7(2y+1))=0

We get rid of parentheses

-y-(7(2y+1))+4+5=0



We calculate terms in parentheses: -(7(2y+1)), so:

7(2y+1)

We multiply parentheses

14y+7

Back to the equation:

-(14y+7)



We add all the numbers together, and all the variables

-1y-(14y+7)+9=0

We get rid of parentheses

-1y-14y-7+9=0

We add all the numbers together, and all the variables

-15y+2=0

We move all terms containing y to the left, all other terms to the right

-15y=-2

y=-2/-15

y=2/15

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