5-1(n-4)=(n+2)

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Solution for 5-1(n-4)=(n+2) equation: 



5-1(n-4)=(n+2)

We move all terms to the left:

5-1(n-4)-((n+2))=0



We calculate terms in parentheses: -((n+2)), so:

(n+2)

We get rid of parentheses

n+2

Back to the equation:

-(n+2)



We get rid of parentheses

-1(n-4)-n-2+5=0

We add all the numbers together, and all the variables

-1n-1(n-4)+3=0

We move all terms containing n to the left, all other terms to the right

-1n-1(n-4)=-3

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