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5-1/2p=p-1
We move all terms to the left:
5-1/2p-(p-1)=0
Domain of the equation: 2p!=0We get rid of parentheses
p!=0/2
p!=0
p∈R
-1/2p-p+1+5=0
We multiply all the terms by the denominator
-p*2p+1*2p+5*2p-1=0
Wy multiply elements
-2p^2+2p+10p-1=0
We add all the numbers together, and all the variables
-2p^2+12p-1=0
a = -2; b = 12; c = -1;
Δ = b2-4ac
Δ = 122-4·(-2)·(-1)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{34}}{2*-2}=\frac{-12-2\sqrt{34}}{-4} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{34}}{2*-2}=\frac{-12+2\sqrt{34}}{-4} $
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