5-2(3-b)=4b-2(b+3)

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Solution for 5-2(3-b)=4b-2(b+3) equation: 



5-2(3-b)=4b-2(b+3)

We move all terms to the left:

5-2(3-b)-(4b-2(b+3))=0

We add all the numbers together, and all the variables

-2(-1b+3)-(4b-2(b+3))+5=0

We multiply parentheses

2b-(4b-2(b+3))-6+5=0



We calculate terms in parentheses: -(4b-2(b+3)), so:

4b-2(b+3)

We multiply parentheses

4b-2b-6

We add all the numbers together, and all the variables

2b-6

Back to the equation:

-(2b-6)



We add all the numbers together, and all the variables

2b-(2b-6)-1=0

We get rid of parentheses

2b-2b+6-1=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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