5-2(3f-4)+7f=20

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Solution for 5-2(3f-4)+7f=20 equation: 



5-2(3f-4)+7f=20

We move all terms to the left:

5-2(3f-4)+7f-(20)=0

We add all the numbers together, and all the variables

7f-2(3f-4)-15=0

We multiply parentheses

7f-6f+8-15=0

We add all the numbers together, and all the variables

f-7=0

We move all terms containing f to the left, all other terms to the right

f=7

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