5-2(3z+)=-4(1-2z)

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Solution for 5-2(3z+)=-4(1-2z) equation:



5-2(3z+)=-4(1-2z)
We move all terms to the left:
5-2(3z+)-(-4(1-2z))=0
We add all the numbers together, and all the variables
-2(+3z)-(-4(-2z+1))+5=0
We multiply parentheses
-6z-(-4(-2z+1))+5=0
We calculate terms in parentheses: -(-4(-2z+1)), so:
-4(-2z+1)
We multiply parentheses
8z-4
Back to the equation:
-(8z-4)
We get rid of parentheses
-6z-8z+4+5=0
We add all the numbers together, and all the variables
-14z+9=0
We move all terms containing z to the left, all other terms to the right
-14z=-9
z=-9/-14
z=9/14

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