5-2(3z+2)=4(1-2z)

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Solution for 5-2(3z+2)=4(1-2z) equation:



5-2(3z+2)=4(1-2z)
We move all terms to the left:
5-2(3z+2)-(4(1-2z))=0
We add all the numbers together, and all the variables
-2(3z+2)-(4(-2z+1))+5=0
We multiply parentheses
-6z-(4(-2z+1))-4+5=0
We calculate terms in parentheses: -(4(-2z+1)), so:
4(-2z+1)
We multiply parentheses
-8z+4
Back to the equation:
-(-8z+4)
We add all the numbers together, and all the variables
-6z-(-8z+4)+1=0
We get rid of parentheses
-6z+8z-4+1=0
We add all the numbers together, and all the variables
2z-3=0
We move all terms containing z to the left, all other terms to the right
2z=3
z=3/2
z=1+1/2

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