5-2(4x+1)=8(x-1)+3

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Solution for 5-2(4x+1)=8(x-1)+3 equation: 



5-2(4x+1)=8(x-1)+3

We move all terms to the left:

5-2(4x+1)-(8(x-1)+3)=0

We multiply parentheses

-8x-(8(x-1)+3)-2+5=0



We calculate terms in parentheses: -(8(x-1)+3), so:

8(x-1)+3

We multiply parentheses

8x-8+3

We add all the numbers together, and all the variables

8x-5

Back to the equation:

-(8x-5)



We add all the numbers together, and all the variables

-8x-(8x-5)+3=0

We get rid of parentheses

-8x-8x+5+3=0

We add all the numbers together, and all the variables

-16x+8=0

We move all terms containing x to the left, all other terms to the right

-16x=-8

x=-8/-16

x=1/2

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