5-2(r-7)=6(r+2)-3r

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Solution for 5-2(r-7)=6(r+2)-3r equation: 



5-2(r-7)=6(r+2)-3r

We move all terms to the left:

5-2(r-7)-(6(r+2)-3r)=0

We multiply parentheses

-2r-(6(r+2)-3r)+14+5=0



We calculate terms in parentheses: -(6(r+2)-3r), so:

6(r+2)-3r

We add all the numbers together, and all the variables

-3r+6(r+2)

We multiply parentheses

-3r+6r+12

We add all the numbers together, and all the variables

3r+12

Back to the equation:

-(3r+12)



We add all the numbers together, and all the variables

-2r-(3r+12)+19=0

We get rid of parentheses

-2r-3r-12+19=0

We add all the numbers together, and all the variables

-5r+7=0

We move all terms containing r to the left, all other terms to the right

-5r=-7

r=-7/-5

r=1+2/5

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