5-2(x+3)+5x=6+2(x-1)+x

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Solution for 5-2(x+3)+5x=6+2(x-1)+x equation: 



5-2(x+3)+5x=6+2(x-1)+x

We move all terms to the left:

5-2(x+3)+5x-(6+2(x-1)+x)=0

We add all the numbers together, and all the variables

5x-2(x+3)-(6+2(x-1)+x)+5=0

We multiply parentheses

5x-2x-(6+2(x-1)+x)-6+5=0



We calculate terms in parentheses: -(6+2(x-1)+x), so:

6+2(x-1)+x

determiningTheFunctionDomain
2(x-1)+x+6

We add all the numbers together, and all the variables

x+2(x-1)+6

We multiply parentheses

x+2x-2+6

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

3x-(3x+4)-1=0

We get rid of parentheses

3x-3x-4-1=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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