5-2(x+3)=4(x+4)

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Solution for 5-2(x+3)=4(x+4) equation: 



5-2(x+3)=4(x+4)

We move all terms to the left:

5-2(x+3)-(4(x+4))=0

We multiply parentheses

-2x-(4(x+4))-6+5=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

-2x-(4x+16)-1=0

We get rid of parentheses

-2x-4x-16-1=0

We add all the numbers together, and all the variables

-6x-17=0

We move all terms containing x to the left, all other terms to the right

-6x=17

x=17/-6

x=-2+5/6

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