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5-2(x-3)=3(x-1)+2
We move all terms to the left:
5-2(x-3)-(3(x-1)+2)=0
We multiply parentheses
-2x-(3(x-1)+2)+6+5=0
We calculate terms in parentheses: -(3(x-1)+2), so:We add all the numbers together, and all the variables
3(x-1)+2
We multiply parentheses
3x-3+2
We add all the numbers together, and all the variables
3x-1
Back to the equation:
-(3x-1)
-2x-(3x-1)+11=0
We get rid of parentheses
-2x-3x+1+11=0
We add all the numbers together, and all the variables
-5x+12=0
We move all terms containing x to the left, all other terms to the right
-5x=-12
x=-12/-5
x=2+2/5
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