5-2(x-4)+3(4-2x)=-(x+4)-8

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Solution for 5-2(x-4)+3(4-2x)=-(x+4)-8 equation: 



5-2(x-4)+3(4-2x)=-(x+4)-8

We move all terms to the left:

5-2(x-4)+3(4-2x)-(-(x+4)-8)=0

We add all the numbers together, and all the variables

-2(x-4)+3(-2x+4)-(-(x+4)-8)+5=0

We multiply parentheses

-2x-6x-(-(x+4)-8)+8+12+5=0



We calculate terms in parentheses: -(-(x+4)-8), so:

-(x+4)-8

We get rid of parentheses

-x-4-8

We add all the numbers together, and all the variables

-1x-12

Back to the equation:

-(-1x-12)



We add all the numbers together, and all the variables

-8x-(-1x-12)+25=0

We get rid of parentheses

-8x+1x+12+25=0

We add all the numbers together, and all the variables

-7x+37=0

We move all terms containing x to the left, all other terms to the right

-7x=-37

x=-37/-7

x=5+2/7

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