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5-2(x-4)=-3(x-5)
We move all terms to the left:
5-2(x-4)-(-3(x-5))=0
We multiply parentheses
-2x-(-3(x-5))+8+5=0
We calculate terms in parentheses: -(-3(x-5)), so:We add all the numbers together, and all the variables
-3(x-5)
We multiply parentheses
-3x+15
Back to the equation:
-(-3x+15)
-2x-(-3x+15)+13=0
We get rid of parentheses
-2x+3x-15+13=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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