5-2(x-4)=3x+5(2x-1)

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Solution for 5-2(x-4)=3x+5(2x-1) equation: 



5-2(x-4)=3x+5(2x-1)

We move all terms to the left:

5-2(x-4)-(3x+5(2x-1))=0

We multiply parentheses

-2x-(3x+5(2x-1))+8+5=0



We calculate terms in parentheses: -(3x+5(2x-1)), so:

3x+5(2x-1)

We multiply parentheses

3x+10x-5

We add all the numbers together, and all the variables

13x-5

Back to the equation:

-(13x-5)



We add all the numbers together, and all the variables

-2x-(13x-5)+13=0

We get rid of parentheses

-2x-13x+5+13=0

We add all the numbers together, and all the variables

-15x+18=0

We move all terms containing x to the left, all other terms to the right

-15x=-18

x=-18/-15

x=1+1/5

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