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5-2(x-6)=2x-4(3x+4)
We move all terms to the left:
5-2(x-6)-(2x-4(3x+4))=0
We multiply parentheses
-2x-(2x-4(3x+4))+12+5=0
We calculate terms in parentheses: -(2x-4(3x+4)), so:We add all the numbers together, and all the variables
2x-4(3x+4)
We multiply parentheses
2x-12x-16
We add all the numbers together, and all the variables
-10x-16
Back to the equation:
-(-10x-16)
-2x-(-10x-16)+17=0
We get rid of parentheses
-2x+10x+16+17=0
We add all the numbers together, and all the variables
8x+33=0
We move all terms containing x to the left, all other terms to the right
8x=-33
x=-33/8
x=-4+1/8
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