5-2(x-7)=3(x+1)+6

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Solution for 5-2(x-7)=3(x+1)+6 equation: 



5-2(x-7)=3(x+1)+6

We move all terms to the left:

5-2(x-7)-(3(x+1)+6)=0

We multiply parentheses

-2x-(3(x+1)+6)+14+5=0



We calculate terms in parentheses: -(3(x+1)+6), so:

3(x+1)+6

We multiply parentheses

3x+3+6

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We add all the numbers together, and all the variables

-2x-(3x+9)+19=0

We get rid of parentheses

-2x-3x-9+19=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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