5-2(y+3)=1-(y+4)

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Solution for 5-2(y+3)=1-(y+4) equation:



5-2(y+3)=1-(y+4)
We move all terms to the left:
5-2(y+3)-(1-(y+4))=0
We multiply parentheses
-2y-(1-(y+4))-6+5=0
We calculate terms in parentheses: -(1-(y+4)), so:
1-(y+4)
determiningTheFunctionDomain -(y+4)+1
We get rid of parentheses
-y-4+1
We add all the numbers together, and all the variables
-1y-3
Back to the equation:
-(-1y-3)
We add all the numbers together, and all the variables
-2y-(-1y-3)-1=0
We get rid of parentheses
-2y+1y+3-1=0
We add all the numbers together, and all the variables
-1y+2=0
We move all terms containing y to the left, all other terms to the right
-y=-2
y=-2/-1
y=+2

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