5-2(y+3)=1-(y+4)

Solution for 5-2(y+3)=1-(y+4) equation:

5-2(y+3)=1-(y+4)

We move all terms to the left:

5-2(y+3)-(1-(y+4))=0

We multiply parentheses

-2y-(1-(y+4))-6+5=0


We calculate terms in parentheses: -(1-(y+4)), so:

1-(y+4)

determiningTheFunctionDomain
-(y+4)+1

We get rid of parentheses

-y-4+1

We add all the numbers together, and all the variables

-1y-3

Back to the equation:

-(-1y-3)


We add all the numbers together, and all the variables

-2y-(-1y-3)-1=0

We get rid of parentheses

-2y+1y+3-1=0

We add all the numbers together, and all the variables

-1y+2=0

We move all terms containing y to the left, all other terms to the right

-y=-2

y=-2/-1

y=+2