5-2(y+3)=4y-1

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Solution for 5-2(y+3)=4y-1 equation: 



5-2(y+3)=4y-1

We move all terms to the left:

5-2(y+3)-(4y-1)=0

We multiply parentheses

-2y-(4y-1)-6+5=0

We get rid of parentheses

-2y-4y+1-6+5=0

We add all the numbers together, and all the variables

-6y=0

y=0/-6

y=0

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