5-2(z-7)=z+1+3z

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Solution for 5-2(z-7)=z+1+3z equation: 



5-2(z-7)=z+1+3z

We move all terms to the left:

5-2(z-7)-(z+1+3z)=0

We add all the numbers together, and all the variables

-2(z-7)-(4z+1)+5=0

We multiply parentheses

-2z-(4z+1)+14+5=0

We get rid of parentheses

-2z-4z-1+14+5=0

We add all the numbers together, and all the variables

-6z+18=0

We move all terms containing z to the left, all other terms to the right

-6z=-18

z=-18/-6

z=+3

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