If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5-2m-3m^2=0
a = -3; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·(-3)·5
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-8}{2*-3}=\frac{-6}{-6} =1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+8}{2*-3}=\frac{10}{-6} =-1+2/3 $
| 14x+5=35° | | 8+2(x−6)=−2+2x−2 | | 2x+14=120 | | 3x-7(8-x)=17 | | 1/2(b+6=3/2b-1 | | 8-2x=2(1-8x)-8 | | 5-3x=50 | | (x+3)/4+(5⋅(7x+9))/3=(3⋅(4x+3))/12−7/2 | | y+23=56 | | 7m+7m=8 | | y=1.5+8.5 | | 3=-5+2k | | m-6+3=13 | | -7-3x=-19 | | 3s-13=-1 | | -1+6k+5k=10 | | -22=n+2=3n | | x8(x−10)=40 | | -26=x-16 | | 5x-3=2×-5 | | (6x-1)(3x+6)=0 | | 5=2r=9 | | 8(y+10)+y=4(y+3)+7 | | (-7/8x)-(3/4)=20 | | 143.65=5(0.07m+19.80+0.20(19.80) | | 17=a+20 | | 3x+4+4x=3x-10+6x | | 1x+4=60 | | 4g-1=15 | | u^2-12=7u | | -4(x+2)-3=20 | | x/3−20=−15 |