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5-2x^2=-43
We move all terms to the left:
5-2x^2-(-43)=0
We add all the numbers together, and all the variables
-2x^2+48=0
a = -2; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·(-2)·48
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*-2}=\frac{0-8\sqrt{6}}{-4} =-\frac{8\sqrt{6}}{-4} =-\frac{2\sqrt{6}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*-2}=\frac{0+8\sqrt{6}}{-4} =\frac{8\sqrt{6}}{-4} =\frac{2\sqrt{6}}{-1} $
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