5-3(20z-20)=-5(14z+19)

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Solution for 5-3(20z-20)=-5(14z+19) equation: 



5-3(20z-20)=-5(14z+19)

We move all terms to the left:

5-3(20z-20)-(-5(14z+19))=0

We multiply parentheses

-60z-(-5(14z+19))+60+5=0



We calculate terms in parentheses: -(-5(14z+19)), so:

-5(14z+19)

We multiply parentheses

-70z-95

Back to the equation:

-(-70z-95)



We add all the numbers together, and all the variables

-60z-(-70z-95)+65=0

We get rid of parentheses

-60z+70z+95+65=0

We add all the numbers together, and all the variables

10z+160=0

We move all terms containing z to the left, all other terms to the right

10z=-160

z=-160/10

z=-16

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