5-3(2x+4)-5x=3-(x-3)+6

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Solution for 5-3(2x+4)-5x=3-(x-3)+6 equation: 



5-3(2x+4)-5x=3-(x-3)+6

We move all terms to the left:

5-3(2x+4)-5x-(3-(x-3)+6)=0

We add all the numbers together, and all the variables

-5x-3(2x+4)-(3-(x-3)+6)+5=0

We multiply parentheses

-5x-6x-(3-(x-3)+6)-12+5=0



We calculate terms in parentheses: -(3-(x-3)+6), so:

3-(x-3)+6

determiningTheFunctionDomain
-(x-3)+3+6

We add all the numbers together, and all the variables

-(x-3)+9

We get rid of parentheses

-x+3+9

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

-11x-(-1x+12)-7=0

We get rid of parentheses

-11x+1x-12-7=0

We add all the numbers together, and all the variables

-10x-19=0

We move all terms containing x to the left, all other terms to the right

-10x=19

x=19/-10

x=-1+9/10

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