5-3(x+2)=4-(2x-2)

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Solution for 5-3(x+2)=4-(2x-2) equation: 



5-3(x+2)=4-(2x-2)

We move all terms to the left:

5-3(x+2)-(4-(2x-2))=0

We multiply parentheses

-3x-(4-(2x-2))-6+5=0



We calculate terms in parentheses: -(4-(2x-2)), so:

4-(2x-2)

determiningTheFunctionDomain
-(2x-2)+4

We get rid of parentheses

-2x+2+4

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

-3x-(-2x+6)-1=0

We get rid of parentheses

-3x+2x-6-1=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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