5-3(x+4)=7+2(x-1)

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Solution for 5-3(x+4)=7+2(x-1) equation: 



5-3(x+4)=7+2(x-1)

We move all terms to the left:

5-3(x+4)-(7+2(x-1))=0

We multiply parentheses

-3x-(7+2(x-1))-12+5=0



We calculate terms in parentheses: -(7+2(x-1)), so:

7+2(x-1)

determiningTheFunctionDomain
2(x-1)+7

We multiply parentheses

2x-2+7

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We add all the numbers together, and all the variables

-3x-(2x+5)-7=0

We get rid of parentheses

-3x-2x-5-7=0

We add all the numbers together, and all the variables

-5x-12=0

We move all terms containing x to the left, all other terms to the right

-5x=12

x=12/-5

x=-2+2/5

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