5-3(x-4)+x=7x-(2x+1)-3x

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Solution for 5-3(x-4)+x=7x-(2x+1)-3x equation: 



5-3(x-4)+x=7x-(2x+1)-3x

We move all terms to the left:

5-3(x-4)+x-(7x-(2x+1)-3x)=0

We add all the numbers together, and all the variables

x-3(x-4)-(7x-(2x+1)-3x)+5=0

We multiply parentheses

x-3x-(7x-(2x+1)-3x)+12+5=0



We calculate terms in parentheses: -(7x-(2x+1)-3x), so:

7x-(2x+1)-3x

We add all the numbers together, and all the variables

4x-(2x+1)

We get rid of parentheses

4x-2x-1

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

-2x-(2x-1)+17=0

We get rid of parentheses

-2x-2x+1+17=0

We add all the numbers together, and all the variables

-4x+18=0

We move all terms containing x to the left, all other terms to the right

-4x=-18

x=-18/-4

x=4+1/2

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