5-3(x-4)=-8+4x+12

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Solution for 5-3(x-4)=-8+4x+12 equation: 



5-3(x-4)=-8+4x+12

We move all terms to the left:

5-3(x-4)-(-8+4x+12)=0

We add all the numbers together, and all the variables

-3(x-4)-(4x+4)+5=0

We multiply parentheses

-3x-(4x+4)+12+5=0

We get rid of parentheses

-3x-4x-4+12+5=0

We add all the numbers together, and all the variables

-7x+13=0

We move all terms containing x to the left, all other terms to the right

-7x=-13

x=-13/-7

x=1+6/7

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