5-3(y-4)=5(y+2)-y

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Solution for 5-3(y-4)=5(y+2)-y equation:



5-3(y-4)=5(y+2)-y
We move all terms to the left:
5-3(y-4)-(5(y+2)-y)=0
We multiply parentheses
-3y-(5(y+2)-y)+12+5=0
We calculate terms in parentheses: -(5(y+2)-y), so:
5(y+2)-y
We add all the numbers together, and all the variables
-1y+5(y+2)
We multiply parentheses
-1y+5y+10
We add all the numbers together, and all the variables
4y+10
Back to the equation:
-(4y+10)
We add all the numbers together, and all the variables
-3y-(4y+10)+17=0
We get rid of parentheses
-3y-4y-10+17=0
We add all the numbers together, and all the variables
-7y+7=0
We move all terms containing y to the left, all other terms to the right
-7y=-7
y=-7/-7
y=1

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