5-3/x=7/2x

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Solution for 5-3/x=7/2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5-(3/x) = (7/2)*x // - (7/2)*x

5-((7/2)*x)-(3/x) = 0

(-7/2)*x-3*x^-1+5 = 0

5*x^0-7/2*x^1-3*x^-1 = 0

(5*x^1-7/2*x^2-3*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^1-7/2*x^2-3*x^0) = 0

x^1

(-7/2)*x^2+5*x-3 = 0

(-7/2)*x^2+5*x-3 = 0

DELTA = 5^2-(-3*4*(-7/2))

DELTA = -17

DELTA < 0

x in { } 

x belongs to the empty set

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