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5-3x(x)=x(3x-13)
We move all terms to the left:
5-3x(x)-(x(3x-13))=0
We calculate terms in parentheses: -(x(3x-13)), so:We get rid of parentheses
x(3x-13)
We multiply parentheses
3x^2-13x
Back to the equation:
-(3x^2-13x)
-3x^2-3xx+13x+5=0
We add all the numbers together, and all the variables
-3x^2+13x-3xx+5=0
We move all terms containing x to the left, all other terms to the right
-3x^2+13x-3xx=-5
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