5-4(3v+1)=1+4(2v+20)

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Solution for 5-4(3v+1)=1+4(2v+20) equation: 



5-4(3v+1)=1+4(2v+20)

We move all terms to the left:

5-4(3v+1)-(1+4(2v+20))=0

We multiply parentheses

-12v-(1+4(2v+20))-4+5=0



We calculate terms in parentheses: -(1+4(2v+20)), so:

1+4(2v+20)

determiningTheFunctionDomain
4(2v+20)+1

We multiply parentheses

8v+80+1

We add all the numbers together, and all the variables

8v+81

Back to the equation:

-(8v+81)



We add all the numbers together, and all the variables

-12v-(8v+81)+1=0

We get rid of parentheses

-12v-8v-81+1=0

We add all the numbers together, and all the variables

-20v-80=0

We move all terms containing v to the left, all other terms to the right

-20v=80

v=80/-20

v=-4

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