5-4(t+3)=17

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Solution for 5-4(t+3)=17 equation: 



5-4(t+3)=17

We move all terms to the left:

5-4(t+3)-(17)=0

We add all the numbers together, and all the variables

-4(t+3)-12=0

We multiply parentheses

-4t-12-12=0

We add all the numbers together, and all the variables

-4t-24=0

We move all terms containing t to the left, all other terms to the right

-4t=24

t=24/-4

t=-6

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