5-4(v+3)=-19-4v+12

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Solution for 5-4(v+3)=-19-4v+12 equation: 



5-4(v+3)=-19-4v+12

We move all terms to the left:

5-4(v+3)-(-19-4v+12)=0

We add all the numbers together, and all the variables

-4(v+3)-(-4v-7)+5=0

We multiply parentheses

-4v-(-4v-7)-12+5=0

We get rid of parentheses

-4v+4v+7-12+5=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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