5-4(z+1)=3(2z-4)

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Solution for 5-4(z+1)=3(2z-4) equation:


Simplifying
5 + -4(z + 1) = 3(2z + -4)

Reorder the terms:
5 + -4(1 + z) = 3(2z + -4)
5 + (1 * -4 + z * -4) = 3(2z + -4)
5 + (-4 + -4z) = 3(2z + -4)

Combine like terms: 5 + -4 = 1
1 + -4z = 3(2z + -4)

Reorder the terms:
1 + -4z = 3(-4 + 2z)
1 + -4z = (-4 * 3 + 2z * 3)
1 + -4z = (-12 + 6z)

Solving
1 + -4z = -12 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
1 + -4z + -6z = -12 + 6z + -6z

Combine like terms: -4z + -6z = -10z
1 + -10z = -12 + 6z + -6z

Combine like terms: 6z + -6z = 0
1 + -10z = -12 + 0
1 + -10z = -12

Add '-1' to each side of the equation.
1 + -1 + -10z = -12 + -1

Combine like terms: 1 + -1 = 0
0 + -10z = -12 + -1
-10z = -12 + -1

Combine like terms: -12 + -1 = -13
-10z = -13

Divide each side by '-10'.
z = 1.3

Simplifying
z = 1.3

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