5-5(4c-7)=50

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Solution for 5-5(4c-7)=50 equation: 



5-5(4c-7)=50

We move all terms to the left:

5-5(4c-7)-(50)=0

We add all the numbers together, and all the variables

-5(4c-7)-45=0

We multiply parentheses

-20c+35-45=0

We add all the numbers together, and all the variables

-20c-10=0

We move all terms containing c to the left, all other terms to the right

-20c=10

c=10/-20

c=-1/2

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