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5-5x=-5/2x+8x
We move all terms to the left:
5-5x-(-5/2x+8x)=0
Domain of the equation: 2x+8x)!=0We add all the numbers together, and all the variables
x∈R
-5x-(+8x-5/2x)+5=0
We get rid of parentheses
-5x-8x+5/2x+5=0
We multiply all the terms by the denominator
-5x*2x-8x*2x+5*2x+5=0
Wy multiply elements
-10x^2-16x^2+10x+5=0
We add all the numbers together, and all the variables
-26x^2+10x+5=0
a = -26; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·(-26)·5
Δ = 620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{620}=\sqrt{4*155}=\sqrt{4}*\sqrt{155}=2\sqrt{155}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{155}}{2*-26}=\frac{-10-2\sqrt{155}}{-52} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{155}}{2*-26}=\frac{-10+2\sqrt{155}}{-52} $
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