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5-5x=5/2x+16
We move all terms to the left:
5-5x-(5/2x+16)=0
Domain of the equation: 2x+16)!=0We get rid of parentheses
x∈R
-5x-5/2x-16+5=0
We multiply all the terms by the denominator
-5x*2x-16*2x+5*2x-5=0
Wy multiply elements
-10x^2-32x+10x-5=0
We add all the numbers together, and all the variables
-10x^2-22x-5=0
a = -10; b = -22; c = -5;
Δ = b2-4ac
Δ = -222-4·(-10)·(-5)
Δ = 284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{284}=\sqrt{4*71}=\sqrt{4}*\sqrt{71}=2\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{71}}{2*-10}=\frac{22-2\sqrt{71}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{71}}{2*-10}=\frac{22+2\sqrt{71}}{-20} $
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