5-6(1+3z)=-29

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Solution for 5-6(1+3z)=-29 equation: 



5-6(1+3z)=-29

We move all terms to the left:

5-6(1+3z)-(-29)=0

We add all the numbers together, and all the variables

-6(3z+1)+5-(-29)=0

We add all the numbers together, and all the variables

-6(3z+1)+34=0

We multiply parentheses

-18z-6+34=0

We add all the numbers together, and all the variables

-18z+28=0

We move all terms containing z to the left, all other terms to the right

-18z=-28

z=-28/-18

z=1+5/9

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