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5-6=x-2+2x^2
We move all terms to the left:
5-6-(x-2+2x^2)=0
We add all the numbers together, and all the variables
-(x-2+2x^2)-1=0
We get rid of parentheses
-2x^2-x+2-1=0
We add all the numbers together, and all the variables
-2x^2-1x+1=0
a = -2; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·(-2)·1
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3}{2*-2}=\frac{-2}{-4} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3}{2*-2}=\frac{4}{-4} =-1 $
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