5-6x+17=3(x-4)

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Solution for 5-6x+17=3(x-4) equation: 



5-6x+17=3(x-4)

We move all terms to the left:

5-6x+17-(3(x-4))=0

We add all the numbers together, and all the variables

-6x-(3(x-4))+22=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

-6x-3x+12+22=0

We add all the numbers together, and all the variables

-9x+34=0

We move all terms containing x to the left, all other terms to the right

-9x=-34

x=-34/-9

x=3+7/9

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